Synthesis and crystal structures of two trigonal bipyramidal Sb(V) compounds, R2SbBr3 and R3Sb(S2PPh2)2 (R=Me3SiCH2)
摘要:
Addition of Br-2 to R2SbBr (R = Me3SiCH2) gives R2SbBr3 (1). R3SbBr2 reacts with NH4S2PPh2 to form R3Sb(S2PPh2)(2), (2). The structures of 1 and 2 have been determined by single-crystal X-ray diffraction. (C) 1999 Elsevier Science S.A. All rights reserved.