base-free dichloride complex (BAIP)ZrCl2 (5) can be prepared from 2 and excess ClSiMe3. The alkylation of 4 or 5 with 2 equiv of MeMgBr, 2 equiv of PhCH2MgCl, and 1 equiv of NaCp(DME) yields the alkyl derivatives (BAIP)ZrR2 (6a, R = Me; 6b, R = CH2Ph) and (BAIP)Zr(η5-C5H5)Cl (8), respectively. The reaction of 2 equiv of PhMe2CCH2MgCl with complex 4 yields the η2-pyridyl complex (BAIP)Zr(η2-N,C−NC5H4)(CH2CMe2Ph)
2当量LiNHAr的反应(AR = 2,6-我
镨2 ç 6 ħ 3)与
1,3-二溴丙烷的产率二胺ArHN(CH 2)3 NHAr((B
AIP)H 2,1)。(B
AIP)H 2与Zr(NMe 2)4的反应产生(B
AIP)Zr(NMe 2)2(2)和2当量的NHMe 2的络合物。化合物2与2当量的[Me 2 NH 2 ] Cl反应生成(B
AIP)ZrCl 2(NHMe 2)2(3)并在过量
吡啶的存在下得到络合物(B
AIP)ZrCl 2 py 2(4)。无碱二
氯化物络合物(B
AIP)ZrCl 2(5)可以由2和过量的ClSiMe 3制备。用2当量的MeMgBr,2当量的PhCH 2 MgCl和1当量的NaCp(
DME)对4或5进行烷基化可得到烷基衍
生物(B
AIP)ZrR 2(6a,R = Me; 6b,R = CH 2 Ph )和(B
AIP基)Zr(η 5 -C 5 H ^ 5)
氯(8), 分别。2当量的PhMe的反应2