摘要:
摘要在有机金属化合物[Ti(OC6H3Pri2-2,6)2(η2-ButNCCH2Ph)(CH2Ph)],[Ti(OC6H3Ph2-2,6)2(C4Et4)]中添加苯胺(PhNH2⩾2当量)和在烃类溶剂中的[Zr(OC6H3But2-2,6)2(CH3)2]导致单核双(苯基酰胺基)衍生物[M(OAr)2(NHPh)2]的形成[M = Ti,OAr = OC6H3Pri2- 2,6(1); M = Ti,OAr = OC6H3Ph2-2,6(2); M = Zr,OAr = OC6H3But2-2,6(3)]。首先用PhNH2(4当量)处理[Hf(CH2Ph)4],然后用HOC6H3But2-2,6(2当量)处理,生成相关的双(苯甲酰氨基)化合物4(M = Hf; OAr = OC6H3But2-2, 6)。两种均配芳基酰胺化合物[M(NHC6H3Pri2-2,6)4] [M = Zr(5)