摘要:
C 6 Me 4(C⋮CH)2 -1,2 [Ar(C⋮CH)2 ]与PPN [Au(acac)2 ]反应(acac =乙酰丙酮,PPN =(Ph 3 P)2 N)(2 :1)或使用[AuCl(SMe 2)]和NEt 3(1:2:2)生成PPN [Au {C⋮CArC⋮CH} 2 ](1)或[Au 2 {μ-Ar(C⋮ C)2 })] n(2)。通式[Au 2 L 2 {μ-Ar(C⋮C)2 }]的双核配合物可以通过2与适当的配体L(1:2)反应而获得[L =t BuNC(3),PMe 3(4),PTo 3(5,To = C 6 H 4 Me-4)]或L 2(1:1)(L 2 = Ph 2 P(CH 2)n PPh 2,n = 4(6),6(7)]。类似的配合物[(AuNHEt 2)2 {μ-Ar(C⋮C)2 }](8)和[{AuC(NH t Bu)(NEt 2)} 2 {μ-Ar(C⋮C)2