O(3) to form XO(2) and O(3)(-). Subsequent rapid reactions of O(3)(-) with general acids produce O(2) and OH. The OH radical reacts rapidly with XO(2)(-) to form a second XO(2) and OH(-). In the O(3)/ClO(2)(-) reaction, ClO(2) and ClO(3)(-) are the final products due to competition between the OH/ClO(2)(-) reaction to form ClO(2) and the OH/ClO(2) reaction to form ClO(3)(-). Unlike ClO(2), BrO(2) is not
臭氧与XO(2)(-)(X = Cl或Br)的反应通过伪一阶条件下过量XO(2)(-)的停止流光谱法进行研究。O(3)/ XO(2)(-)反应在[O(3)]和[XO(2)(-)]中是一阶反应,速率常数k(1)(Cl)= 8.2(4 )x 10(6)M(-1)s(-1)和k(1)(Br)= 8.9(3)x 10(4)M(-1)s(-1)在25.0摄氏度和= 1.0M。拟议的速率确定步骤是电子从XO(2)(-)转移到O(3)以形成XO(2)和O(3)(-)。O(3)(-)与普通酸的随后快速反应产生O(2)和OH。OH自由基与XO(2)(-)快速反应,形成第二个XO(2)和OH(-)。在O(3)/ ClO(2)(-)反应中,由于OH / ClO(2)(-)反应形成ClO之间的竞争,ClO(2)和ClO(3)(-)是最终产物(2)和OH / ClO(2)反应形成ClO(3)(-)。与ClO(2)不