Phosphorus–fluorine chemistry. Part XX. Redox disproportionation of difluorophosphines, RPF<sub>2</sub>, with electronegative substituents R
作者:H. G. Ang、R. Schmutzler
DOI:10.1039/j19690000702
日期:——
Difluorophosphines, RPF2, containing the electronegative substituents, R = CF3 and C6H5, will undergo redox disproportionation with formation of tetrafluorophosphoranes and cyclopolyphosphines, in accord with the overall equation 10 RPF2→ 5 RPF4+(RP)n(n= 4, 5 for R = CF3; n= 5 for R = C6H5). The identity of the products, all previously known, was established by comparison of their physical properties
Difluorophosphines,RPF 2,含有电负性取代基,R = CF 3和C 6 H ^ 5,将发生氧化还原歧化以形成tetrafluorophosphoranes和cyclopolyphosphines的,在符合总方程式10 RPF 2 → 5 RPF 4 +(RP)Ñ(ñ = 4,5为R = CF 3 ; ñ = 5对于R = C 6 H ^ 5)。通过比较产品的物理性质(nmr和质谱,ir光谱,X-射线粉末图等)。