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trans-hydridoamidobis(tricyclohexylphosphine)platinum | 110719-81-8

中文名称
——
中文别名
——
英文名称
trans-hydridoamidobis(tricyclohexylphosphine)platinum
英文别名
——
trans-hydridoamidobis(tricyclohexylphosphine)platinum化学式
CAS
110719-81-8
化学式
C36H69NP2Pt
mdl
——
分子量
772.978
InChiKey
MOFYEVAGJFGTAA-UHFFFAOYSA-N
BEILSTEIN
——
EINECS
——
  • 物化性质
  • 计算性质
  • ADMET
  • 安全信息
  • SDS
  • 制备方法与用途
  • 上下游信息
  • 反应信息
  • 文献信息
  • 表征谱图
  • 同类化合物
  • 相关功能分类
  • 相关结构分类

计算性质

  • 辛醇/水分配系数(LogP):
    12.07
  • 重原子数:
    40.0
  • 可旋转键数:
    8.0
  • 环数:
    6.0
  • sp3杂化的碳原子比例:
    1.0
  • 拓扑面积:
    26.02
  • 氢给体数:
    1.0
  • 氢受体数:
    1.0

上下游信息

  • 下游产品
    中文名称 英文名称 CAS号 化学式 分子量

反应信息

  • 作为反应物:
    描述:
    参考文献:
    名称:
    铂(II)单体和二聚酰胺配合物的合成和反应化学
    摘要:
    A series of complexes trans-[PtH(NH3)L2]ClO4 (L = PPh3, PEt3, PCy3), trans-[PtMe(NH3)L2]ClO4 (L = PPh3, PEt3, PMePh2, PCy3), and [PtMe(NH3)dppe]ClO4 have been synthesized from trans-PtH(ClO4)L2, trans-PtMe(ClO4)L2, and PtMe(ClO4)dppe and ammonia, respectively. Reacting trans-[PtH(NH3)L2]ClO4 (L = PPh3, PEt3) with NaNH2 gives [PtH(mu-NH2)L]2 as a mixture of anti and syn isomers. The complexes reductively eliminate ammonia. Reacting trans-[PtMe(NH3)L2]ClO4 (L = PPH3, PEt3, PMePh2) with NaNH2 gives the stable complexes [PtMe(mu-NH2)L]2 as mixtures of anti and syn isomers. For L = PPh3, PMePh2, PEt3, the percentage anti isomer is 100, 75, and 50, respectively. For L = PEt3, the intermediate complex trans-PtMe(NH2)(PEt3)2 has been observed. Reacting [PtMe(mu-NH2)L]2 with L (L = PPh3, PEt3) gives cis-PtMe(NH2)L2. Reacting trans-[PtH(NH3)(PCy3)2]ClO4, trans-[PtMe(NH3)(PCy3)2]ClO4, or trans-[PtPh(NH3)(PCy3)2]ClO4 with NaNH2 gives trans-PtH(NH2)(PCy3)2, trans-PtMe(NH2)(PCy3)2, or trans-PtPh(NH2)(PCy3)2. Reacting [PtMe(mu-Cl)PCy3]2 with AgClO4 then NH3 gives [PtMe(NH3)2PCy3]ClO4. Treating [PtMe(NH3)2PCy3] with NaNH2 gives an equimolar mixutre of anti and syn isomers of [PtMe(mu-NH2)PCy3]2. The syn isomer, which has been isolated, converts to a mixture of syn and anti in the presence of tricyclohexylphosphine in CDCl3 solution. The compound anti-[PtMe(mu-NH2)PPh3]2 crystallizes in the space group C2/c with a = 22.592 (5) angstrom, b = 11.844 (3) angstrom, c = 29.403 (6) angstrom, beta = 116.43 (2) degrees, and Z = 8. The two crystallographically independent molecules with Pt(1)-Pt(1A) and Pt(2)-Pt(2A) distances of 3.106 (1) and 3.117 (1) angstrom, respectively, are associated by Pt...H interactions. The complex trans-PtMe(NH2)(PCy3)2 reacts with CF3SO3H to give trans-[PtMe(NH3)(PCy3)2]CF3SO3. The complex trans-PtPh(NH2)(PCy3)2 reacts with CF3SO3H and H2O to give trans-[PtPh(NH3)(PCy3)2]CF3SO3 and trans-PtPh(NH2)(PCy3)2 reacts with methyl iodide and allyl chloride to give trans-PtPhI(PCy3)2 and trans-PtPhCl(PCy3)2, respectively. Carbon dioxide reacts with trans-PtPh(NH2)(PCy3)2 to give trans-PtPh(NHCO2H)(PCy3)2 then trans-PtPh(OCONH2)(PCy3)2.
    DOI:
    10.1021/om00049a020
  • 作为产物:
    描述:
    Pt(PCy3)2(H)(Cl) 在 NH3 、 NaNH2 作用下, 以 甲醇氯仿氘代苯 为溶剂, 生成 trans-hydridoamidobis(tricyclohexylphosphine)platinum
    参考文献:
    名称:
    铂(II)单体和二聚酰胺配合物的合成和反应化学
    摘要:
    A series of complexes trans-[PtH(NH3)L2]ClO4 (L = PPh3, PEt3, PCy3), trans-[PtMe(NH3)L2]ClO4 (L = PPh3, PEt3, PMePh2, PCy3), and [PtMe(NH3)dppe]ClO4 have been synthesized from trans-PtH(ClO4)L2, trans-PtMe(ClO4)L2, and PtMe(ClO4)dppe and ammonia, respectively. Reacting trans-[PtH(NH3)L2]ClO4 (L = PPh3, PEt3) with NaNH2 gives [PtH(mu-NH2)L]2 as a mixture of anti and syn isomers. The complexes reductively eliminate ammonia. Reacting trans-[PtMe(NH3)L2]ClO4 (L = PPH3, PEt3, PMePh2) with NaNH2 gives the stable complexes [PtMe(mu-NH2)L]2 as mixtures of anti and syn isomers. For L = PPh3, PMePh2, PEt3, the percentage anti isomer is 100, 75, and 50, respectively. For L = PEt3, the intermediate complex trans-PtMe(NH2)(PEt3)2 has been observed. Reacting [PtMe(mu-NH2)L]2 with L (L = PPh3, PEt3) gives cis-PtMe(NH2)L2. Reacting trans-[PtH(NH3)(PCy3)2]ClO4, trans-[PtMe(NH3)(PCy3)2]ClO4, or trans-[PtPh(NH3)(PCy3)2]ClO4 with NaNH2 gives trans-PtH(NH2)(PCy3)2, trans-PtMe(NH2)(PCy3)2, or trans-PtPh(NH2)(PCy3)2. Reacting [PtMe(mu-Cl)PCy3]2 with AgClO4 then NH3 gives [PtMe(NH3)2PCy3]ClO4. Treating [PtMe(NH3)2PCy3] with NaNH2 gives an equimolar mixutre of anti and syn isomers of [PtMe(mu-NH2)PCy3]2. The syn isomer, which has been isolated, converts to a mixture of syn and anti in the presence of tricyclohexylphosphine in CDCl3 solution. The compound anti-[PtMe(mu-NH2)PPh3]2 crystallizes in the space group C2/c with a = 22.592 (5) angstrom, b = 11.844 (3) angstrom, c = 29.403 (6) angstrom, beta = 116.43 (2) degrees, and Z = 8. The two crystallographically independent molecules with Pt(1)-Pt(1A) and Pt(2)-Pt(2A) distances of 3.106 (1) and 3.117 (1) angstrom, respectively, are associated by Pt...H interactions. The complex trans-PtMe(NH2)(PCy3)2 reacts with CF3SO3H to give trans-[PtMe(NH3)(PCy3)2]CF3SO3. The complex trans-PtPh(NH2)(PCy3)2 reacts with CF3SO3H and H2O to give trans-[PtPh(NH3)(PCy3)2]CF3SO3 and trans-PtPh(NH2)(PCy3)2 reacts with methyl iodide and allyl chloride to give trans-PtPhI(PCy3)2 and trans-PtPhCl(PCy3)2, respectively. Carbon dioxide reacts with trans-PtPh(NH2)(PCy3)2 to give trans-PtPh(NHCO2H)(PCy3)2 then trans-PtPh(OCONH2)(PCy3)2.
    DOI:
    10.1021/om00049a020
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文献信息

  • Park, Soonheum; Roundhill, D. Max; Rheingold, Arnold L., Inorganic Chemistry, 1987, vol. 26, # 24, p. 3972 - 3974
    作者:Park, Soonheum、Roundhill, D. Max、Rheingold, Arnold L.
    DOI:——
    日期:——
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