通过三个当量的反应形成醇盐Bi [OCMe 2(2-C 4 H 3 S)] 3(1)。用Bi(O t Bu)3制备醇HOCMe 2(2-C 4 H 3 S),然后
水解得到
铋氧化簇[Bi 4 O 2 OCMe 2(2-C 4 H 3 S)} 8 ] (2)。相反,Bi(O t Bu)3和Bi [N(SiMe 3)2 ] 3的反应与
硅烷醇HOSiMe 2(2-C 4 H 3 X)(X = O,S,Se和NMe),HOSiMe 2(2-C 4 H 2 S-5-SiMe 3)和HOSiMe 2(3-C 4 H 3 S)导致形成三(杂芳基)双突变蛋白Bi(2-C 4 H 2 X-5-R)3 [其中X = O,R = H(3); X = S,R = H(4);X = S,R = SiMe 3(5);X = NMe,R = H(6); X = Se,R = H(7)]和Bi(3-C 4 H 3 S)3(