Thermal Alkylation of Ambidentate Lactams with 2-(Perfluoroalkyl)-1-iodoalkanes. The Effect of Reaction Conditions and Ring Size on the Synthesis of 2-(Perfluoroalkyl)ethanols and the Mechanism of Reaction
摘要:
The perfluoroalkylated long chain alcohol and their derivatives exhibit strong surface activity in solution and novel surface modification properties as adsorbed layers or films. A new, little known synthesis of 2-(perfluoroalkyl)ethanols (R(F)CH(2)CH(2)OH) employs a lactam, e.g., 2-pyrrolidinone (2), with an iodoalkane, e.g., C6F13CH2CH2I (1) Alkylation of 2 by heating with 1 gives C6F13CH2CH2OH (3) in 83% distilled yield, and treating the residual lactim ether salt (6 HI) with K2CO3 gives additional 3, up to 94% yield. Rate of alcohol formation (k(alc)) is unaffected by molar ratio of 2:1, yet rate of 1 reaction (k(iodo)) increases 2.44 times with doubling of 2:1 and side product C6F13CH=CH2 (4) decreases from 4 to 2%. For homologous lactams [(CH2)(n)NHC=O] (n = 3-5), selectivities (mel 3:4) are as follows: 5-membered ring, 18.4; 6-membered ring, 0.73; 7-membered ring, 0.13. Conversions to 3 are as follows: 6-membered ring, 19.4%; and 7-membered ring, 1.75%, Table 13. A three-step mechanism is proposed: (1) O-alkylation of the lactam by 1 gives lactim salt I; (2) N-substitution of salt I by another molecule of lactam forms a tetrahedral adduct (II); (3) breakdown of salt II gives 3 and iminolactam salt III. In model experiments, heating of 2 and lactim 6 yields 99% of 3 and iminolactam 5 and 1% of 4. By contrast, 7-membered 14 with 2 gives 45% of 3 and iminolactam 12, besides 4 and epsilon-caprolactam 10 (20%). For higher lactams, two competitive reactions can be discerned: (1) the S(N)2 displacement of alcohol by N-attack on salt II and a unimolecular, concerted fragmentation of the lactim, to lactam and alkene.
The Effect of Ring Size on Tetrahedral Displacement Reactions of Cyclic Imidates. Synthesis of O-(Fluoroalkyl)lactim and Higher O-Alkyllactims from Lower O-Alkyllactims
摘要:
A recently developed synthesis of 2-(perfluoroalkyl)ethanols (R(F)CH(2)CH(2)OH) is based on heating 2-(perfluoroalkyl)-1-iodoethanes R(F)CH(2)CH(2)I with an amide, e.g., N-methylformamide or a lactam, 2-pyrrolidinone. The presumed O-[2-(perfluoroalkyl)ethyl]lactim intermediates have now been prepared in good to excellent yields (60-90%) by heating a lower molecular mass O-alkyllactim with a higher-boiling alcohol, e.g., with R(F)CH(2)CH(2)OH, to displace the lower boiling alcohol. Competitive rate experiments showed that a 7-membered O-methyllactim reacted four to five times faster than did the 5-membered O-methyllactim. This difference is attributed to increased eclipsing strain, commonly called ''I-strain''. In a ''planar'' 5-membered lactim ring, the engendered eclipsing strain appears to be greater than in the more flexible 7-membered ring. Reactant ratio and reaction conditions also affected the yield of lactim ether. Preparatively, reaction of C6F13CH2CH2OH (3) with O-ethylbutyrolactim (6) gave O-[2-(perfluorohexyl)ethyl]butyrolactim (7) in an 89.2% yield (on unrecovered 3) at 67.9% conversion. Yield was limited by dealkylation and condensation reactions that occurred during long heating times. By contrast, alcohol 3 with O-methylcaprolactim (10) gave 7-membered O-[2-(F-hexyl)ethyl]caprolactim (11) in 98% yield at 90% conversion.
2-(Perfluoroalkyl)ethanols by Thermal Alkylation of Ambidentate Lactams with 2-(Perfluoroalkyl)-1-iodoalkanes, in the Presence of Added Water. A Change in Mechanism and Stoichiometry of the Reaction. Isolation of a Water Adduct of the Lactim Ether Intermediate
作者:Neal O. Brace
DOI:10.1021/jo960831g
日期:1996.1.1
Thermal alkylation of amides by an alkyl halide gives alcohols and esters, and the intriguing behavior of ambidentate lactams in this reaction with 2-(perfluoroalkyl)-1-iodoethanes and lactam 2 is summarized in Scheme 1. 2-(Perfluoroalkyl)ethanols (3) are the principal alkylation product, and there is obtained a range of coproducts in varying amounts. A lactimether salt (6.HI) is the first reaction
流程1中概述了酰胺与烷基卤的热烷基化反应生成醇和酯,歧化内酰胺在与2-(全氟烷基)-1-碘乙烷和内酰胺2的反应中表现出令人着迷的行为.2-(全氟烷基)乙醇(3 )是主要的烷基化产物,并且获得了各种量的副产物。乳酸亚胺醚盐(6.HI)是一系列反应中的第一个反应中间体。对于δ-戊内酰胺(8)或ε-己内酰胺(11),转化为3的幅度急剧下降,R(F)CH = CH(2)(4)成为主要产品。然而,当引入水时,碘代烷1的2的烷基化速率增加,向3和4的转化率降低,并形成了新的内酰胺醚盐7.HI(6.HI的水加合物)。由于副产物2弱碱性且平衡位于碱性胺盐(7.HI)一侧,抑制了向3的转化。2-羟基-2-[[[(((2-(全氟己基)乙基]氧基]吡咯烷)的质谱图包括母体离子和带有羟基的完整吡咯烷环的片段(m / z = 131) 。在质子溶剂中含有7.HI的产物混合物的碱性水解可得到3和2的高产率。较高的内酰
Brace Neal O., Davidson Barbara C., Shellhamer Dale F., Daniels Mirna, J. Org. Chem, 59 (1994) N 13, S 3670-3675