[Ag(NH = CMe2)2]
ClO4与顺式[PtC
L2L2]的摩尔比为1:1的反应生成顺式[PtCl(NH = CMe2)(PPh3)2] (1cis)或顺式[PtCl (NH = CMe2)2(dmso)] (2),并以2:1摩尔比产生[Pt(NH = CMe2)2
L2]( )2 [L = PPh3(3),
L2 = tbbpy =
4,4'-二叔丁基-2,2'-二吡啶基(4)]。配合物2与PPh3(1:2)反应生成反式-[PtCl(NH = CMe2)(PPh3)2] ClO(4)(1trans)。顺式-[PtC
L2(dmso)2],[Au(NH = CMe2)(PPh3)] 和PPh3(1:1:1)的两步反
应得到[
SP-4-3]-[PtCl( NH = CMe 2)(dmso)(PPh 3)] ClO 4(5)。配合物2和4与PhIC
L2的反应产生了