Three-Component Condensation of Urea with Formaldehyde and Propane-1,3-diamine or Butane-1,4-diamine
作者:F. Hamoud、Y. Bedouh、S. M. Ramsh、E. S. Khrabrova
DOI:10.1134/s1070363221110116
日期:2021.11
Three-component condensation of urea with formaldehyde and propane-1,3-diamine in a molar ratio of 1 : 3 : 1 leads to the tricyclic 1,3,5,7,11,13,15,17-octaazatricyclo[15.3.1.17,11]docosane-4,14-dione. Condensation of urea with 1,3,7,9,13,15,19,21-octaazapentacyclo[19.3.1.13,7.19,13.115,19]octacosane (2 : 1) also leads to the formation of tricyclic product. As a result of the condensation of urea with formaldehyde
摘要 尿素与甲醛和丙烷-1,3-二胺以 1:3:1 的摩尔比进行三组分缩合生成三环 1,3,5,7,11,13,15,17-八氮杂三环 [15.3. 1.1 7,11 ]二十二烷-4,14-二酮。尿素与 1,3,7,9,13,15,19,21-octaazapentacyclo[19.3.1.1 3,7 .1 9,13 .1 15,19 ] octacosane (2:1) 的缩合也导致形成三环产物。由于尿素与甲醛和丁烷-1,4-二胺以 2 : 4 : 1 的比例缩合,5,5'-丁烷-1,4-二基双(1,3,5-triazinan-2 - 一)获得。