A method for preparing asymmetric 3,4′-(hexafluroisopropylidene) dipthalic anhydride (a-6FDA) and asymmetric 3,4′-(methylene)diphthalic anhydride (a-MDPA) from asymmetric 2,3,3′,4′-benzophenone dianhydride (a-BTDA). First, a-BTDA is converted to its corresponding N-alkyl or N-phenyl bisimides by reacting with either methylamine or aniline. The sequential addition of two trifluoromethyl (CF3) groups to the carbonyl unit of a-BTDA produce the corresponding bisimides of asymmetric 6FDA, which is hydrolyzed to the asymmetric 6F-tetracarboxylic acid followed by cyclodehydration to obtain asymmetric 6F-dianhydride (a-6FDA). Separately, the carbonyl unit of bisimides of a-BTDA is reduced to a methylene unit to afford the corresponding bisimides of asymmetric 3,4′-(methylene)diphthalic anhydride, which is hydrolyzed to the asymmetric methylene tetracarboxylic acid followed by cyclodehydration to obtain 3,4′-(methylene)diphthalic anhydride (a-MDPA).
一种制备不对称3,4'-(六
氟异丙基亚甲基)
二苯酐(a-
6FDA)和不对称3,4'-(亚甲基)
二苯酐(a-MDPA)的方法,从不对称2,3,3',4'-苯并酮二酸酐(a-
BTDA)开始。首先,a-
BTDA通过与
甲胺或
苯胺反应转化为相应的N-烷基或N-苯基双
亚胺。将两个三
氟甲基(
CF3)依次加到a-
BTDA的羰基单元上,产生不对称
6FDA的相应双
亚胺,其
水解为不对称6F-四
羧酸,随后通过环缩脱
水反应获得不对称6F-二酸酐(a-
6FDA)。另外,将a-
BTDA的双
亚胺的羰基单元还原为亚甲基单元,可得到相应的不对称3,4'-(亚甲基)
二苯酐的双
亚胺,其
水解为不对称亚甲基四
羧酸,随后通过环缩脱
水反应获得3,4'-(亚甲基)
二苯酐(a-MDPA)。