Reactions of Cp*Ir(2,5-dimethylthiophene) with Ru<sub>3</sub>(CO)<sub>12</sub>, Re<sub>2</sub>(CO)<sub>10</sub>, Mn<sub>2</sub>(CO)<sub>10</sub>, and [(η<sup>6</sup>-C<sub>6</sub>H<sub>6</sub>)RuCl<sub>2</sub>]<sub>2</sub>
作者:Jiabi Chen、Victor G. Young,、Robert J. Angelici
DOI:10.1021/om960078h
日期:1996.6.11
is 2,5-dimethylthiophene, with Ru3(CO)12, Re2(CO)10, Mn2(CO)10, and [(η6-C6H6)RuCl2]2 yield a remarkable diversity of products. With Ru3(CO)12, both 1 and 2 give the CO-substituted product Cp*Ir(η4-2,5-Me2T·Ru3(CO)11) (4), in which the 2,5-Me2T group is η4-coordinated to the Ir and S-coordinated to a Ru in the plane of the triangular Ru3(CO)11 cluster. With Re2(CO)10, 1 reacts to give the CO-substituted
异构体的Cp *的Ir(η的反应4 -2,5--ME 2 T)(1)1和Cp *的Ir(Ç,š -2,5--ME 2 T)(2),其中2,5-ME 2 T是2,5-二甲基噻与孺3(CO)12中,Re 2(CO)10,锰2(CO)10,和[(η 6 -C 6 H ^ 6)的RuCl 2 ] 2产率的显着的多样性产品。用的Ru 3(CO)12,二者1和2得到CO-取代的Cp产物*的Ir(η 4 -2,5--ME 2 T·孺3(CO)11)(4),其中,所述2,5--ME 2 T组是η 4配位的给Ir和S与三角形Ru 3(CO)11簇的平面中的Ru协调。随Re 2(CO)10,1个反应得到的CO取代的Cp产物*的Ir(η 4 -2,5--ME 2 T·重新2(CO)9)(6),其中1是S-协调在金属-金属二聚体Re的赤道位置2(CO)9。然而,该反应的另一产物为Cp *的Ir(η 4 -SC 3