[EN] PROCESS FOR THE SYNTHESIS OF 1,3-DIHYDRO-IMIDAZO[4,5-B]PYRIDIN-2-ONE AND/OR DERIVATIVES THEREOF<br/>[FR] PROCÉDÉ DE SYNTHÈSE DE 1,3-DIHYDRO-IMIDAZO[4,5-B]PYRIDIN-2-ONE ET/OU DE SES DÉRIVÉS
申请人:[en]SIEGFRIED AG
公开号:WO2022218811A1
公开(公告)日:2022-10-20
The present invention relates to a novel method of producing a compound of Formula (I) from a compound of formula (II) by a novel cyclisation process, as well as a method of producing an acid adduct of the compound of Formula (I) wherein L represents a leaving group, and R represents hydrogen, a substituted or unsubstituted linear, branched and/or cyclic alkyl group that may contain one or more hetero atoms in the linear, branched and/or cyclic alkyl chain, a substituted or unsubstituted aromatic or heteroaromatic group, a substituted or unsubstituted linear, branched and/or cyclic aralkyl or heteroaromatic alkyl group that may contain one or more hetero atoms in the linear, branched and/or cyclic alkanediyl chain, or a substituted or unsubstituted alkylaryl or alkyl heteroaromatic group with at least one linear, branched and/or cyclic alkyl residue that may contain one or more hetero atoms in the linear, branched and/or cyclic alkyl chain.
Development of Two Complementary Syntheses for a Privileged CGRP Receptor Antagonist Substructure
作者:David K. Leahy、Lopa V. Desai、Rajendra P. Deshpande、Antony V. Mariadass、Sundaramurthy Rangaswamy、Santhosh K. Rajagopal、Lakshmi Madhavan、Shashidhar Illendula
DOI:10.1021/op2003634
日期:2012.2.17
1-(Piperidin-4-yl)-1H-imidazo[4,5-b]pyridin-2(3H)-one (1) is a privileged substructure found in >1000 unique CGRP receptor antagonists. Two practical and efficient syntheses of 1 are described from complementary starting materials. One route features a chemoselective reductiveamination, while the second route utilizes a Pd-catalyzed amination using an ammonia surrogate to overcome an issue of poor
1-(哌啶-4-基)-1 H-咪唑并[4,5 - b ]吡啶-2(3 H)-一(1)是在> 1000种独特CGRP受体拮抗剂中发现的特权亚结构。由互补的起始原料描述了两种实用且有效的1的合成方法。一种途径具有化学选择性还原胺化作用,而第二种途径利用氨替代物利用钯催化的胺化作用来克服选择性差的问题。