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Trimethylsilylmethylantimony dibromide | 149970-13-8

中文名称
——
中文别名
——
英文名称
Trimethylsilylmethylantimony dibromide
英文别名
dibromo(trimethylsilylmethyl)stibane
Trimethylsilylmethylantimony dibromide化学式
CAS
149970-13-8
化学式
C4H11Br2SbSi
mdl
——
分子量
368.775
InChiKey
HXZXFQAHUSGOMB-UHFFFAOYSA-L
BEILSTEIN
——
EINECS
——
  • 物化性质
  • 计算性质
  • ADMET
  • 安全信息
  • SDS
  • 制备方法与用途
  • 上下游信息
  • 反应信息
  • 文献信息
  • 表征谱图
  • 同类化合物
  • 相关功能分类
  • 相关结构分类

计算性质

  • 辛醇/水分配系数(LogP):
    3.14
  • 重原子数:
    8
  • 可旋转键数:
    1
  • 环数:
    0.0
  • sp3杂化的碳原子比例:
    1.0
  • 拓扑面积:
    0
  • 氢给体数:
    0
  • 氢受体数:
    0

反应信息

  • 作为反应物:
    描述:
    Trimethylsilylmethylantimony dibromide 在 lithium aluminium tetrahydride 作用下, 以 further solvent(s) 为溶剂, 以51.4%的产率得到trimethylsilylmethylstibine
    参考文献:
    名称:
    Primary and secondary trimethylsilylmethylstibines. Synthesis, characterization and chemical vapor deposition properties
    摘要:
    The primary and secondary trimethylsilylmethylstibines (trimethylsilylmethyl = Me3SiCH2-) (Me3SiCH2)SbH2 and (Me3SiCH2)2SbH have been synthesized by the reduction of a corresponding dihalo- and monohaloantimony compound, respectively. Trimethylsilylmethylstibine was prepared by the reduction of (Me3SiCH2)SbBr2 With lithium aluminum hydride (LAH) in tetraglyme. The primary stibine is highly air-sensitive and exhibits a vapor pressure of 2.0 Torr at 0-degrees-C. Bis-(trimethytsilylmethyl)stibine was synthesized by the LAH reduction of either (Me3SiCH2)2SbBr or (Me3SiCH2)2SbI in diethyl ether, The secondary stibine is less sensitive to air than (Me3SiCH2)SbH2 but nonetheless decomposes quickly when exposed to air. The detailed synthesis, spectroscopic characterizations and physical properties of both stibines, as well as the preliminary chemical vapor deposition experiments of (Me3SiCH2)SbH2, are discussed.
    DOI:
    10.1016/0022-328x(93)80114-q
  • 作为产物:
    描述:
    参考文献:
    名称:
    Synthesis and crystal structures of two trigonal bipyramidal Sb(V) compounds, R2SbBr3 and R3Sb(S2PPh2)2 (R=Me3SiCH2)
    摘要:
    Addition of Br-2 to R2SbBr (R = Me3SiCH2) gives R2SbBr3 (1). R3SbBr2 reacts with NH4S2PPh2 to form R3Sb(S2PPh2)(2), (2). The structures of 1 and 2 have been determined by single-crystal X-ray diffraction. (C) 1999 Elsevier Science S.A. All rights reserved.
    DOI:
    10.1016/s0022-328x(99)00385-x
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