Formation of [Cp2TiSbMe2]2, [Cp2TiSb(SiMe3)2]2 and [Cp2TiCl]2·2Mes4Sb2
摘要:
Reactions of [Cp2Ti(btmsa)] (btmsa = bis(trimethylsilyl)acetylene) with R4Sb2 (R = Me, Me3Si) give [Cp2TiSbMe2](2) (1) or [Cp2TiSb(SiMe3)(2)](2) (2) respectively. [Cp2TiCl](2)center dot 2Mes(4)Sb(2) (3) is serendipitously formed from [Cp2Ti(btmsa)] and Mes(2)SbH containing NH4Cl traces. (c) 2010 Elsevier B.V. All rights reserved.