para-Hydrogen enhanced NMR signals are used to show that NBu4[M(CO)2I2] (M = Rh, Ir) add hydrogen to form NBu4- all-cis-[M(H)2(CO)2I2]} which for M = Ir undergoes H2 elimination in a step where ΔH‡ 106 ± 10 kJ mol–1 and ΔS‡± 6 J K–1 mol–1 while showing a rich substitution chemistry with PPh3 that leads to both charged and neutral products via square pyramidal Ir(H)2(CO)2I.
对氢增强的 NMR 信号被用来显示 NBu4[M(CO)2I2] (M = Rh、M=Ir)加入氢形成 NBu4- 全顺式-[M(H)2(CO)2I2]},其中 M = Ir 在 ΔH‡ 106 ± 10 kJ mol-1 和 ΔS‡± 6 J K-1 mol-1 的步骤中发生 H2 消去,同时与 PPh3 发生丰富的取代
化学反应,通过方形
金字塔 Ir(H)2(CO)2I 产生带电和中性产物。