摘要:
                                [Ag(NH = CMe2)2] ClO4与顺式[PtCl2L2]的摩尔比为1:1的反应生成顺式[PtCl(NH = CMe2)(PPh3)2] ClO4(1cis)或顺式[PtCl (NH = CMe2)2(dmso)] ClO4(2),并以2:1摩尔比产生[Pt(NH = CMe2)2L2](ClO4)2 [L = PPh3(3),L2 = tbbpy = 4,4'-二叔丁基-2,2'-二吡啶基(4)]。配合物2与PPh3(1:2)反应生成反式-[PtCl(NH = CMe2)(PPh3)2] ClO(4)(1trans)。顺式-[PtCl2(dmso)2],[Au(NH = CMe2)(PPh3)] ClO4和PPh3(1:1:1)的两步反应得到[SP-4-3]-[PtCl( NH = CMe 2)(dmso)(PPh 3)] ClO 4(5)。配合物2和4与PhICl2的反应产生了