Ruthenium–tin complexes from the reaction of HSnPh3 with Ru3(CO)10(NCMe)2 and their reactions with bis(tri-t-butylphosphine)platinum
作者:Richard D. Adams、Burjor Captain、Eszter Trufan
DOI:10.1016/j.jorganchem.2008.08.033
日期:2008.11
compounds Ru 3 (CO) 9 (SnPh 3 ) 2 (NCMe)(μ-H) 2 ( 1 ) , Ru 3 (CO) 10 (SnPh 3 ) 2 (μ-H) 2 ( 2 ) , Ru(CO) 4 (SnPh 3 ) 2 ( 3 ) and Ru(CO) 4 (SnPh 3 )(H) ( 4 ) were obtained from the reaction of Ru 3 (CO) 10 (NCMe) 2 with HSnPh 3 in hexane solvent. Compounds 1 , 3 and the new compound Ru 3 (CO) 7 (SnPh 3 ) 3 (NCMe) 2 (μ-H) 3 ( 5 ) were obtained from reaction of Ru 3 (CO) 10 (NCMe) 2 with HSnPh 3 in a CH 2 Cl 2
化合物 Ru 3 (CO) 9 (SnPh 3 ) 2 (NCMe)(μ-H) 2 ( 1 ) , Ru 3 (CO) 10 (SnPh 3 ) 2 (μ-H) 2 ( 2 ) , Ru(CO ) 4 (SnPh 3 ) 2 ( 3 ) 和 Ru(CO) 4 (SnPh 3 )(H) ( 4 ) 由 Ru 3 (CO) 10 (NCMe) 2 与 HSnPh 3 在己烷溶剂中的反应获得。化合物1、3和新化合物Ru 3 (CO) 7 (SnPh 3 ) 3 (NCMe) 2 (μ-H) 3 ( 5 )由Ru 3 (CO) 10 (NCMe) 2 与HSnPh 3 反应得到在 CH 2 Cl 2 和 MeCN 溶剂混合物中。化合物2和新化合物Ru 3 (CO) 9 (SnPh 3 ) 3 (μ-H) 3 ( 6 )分别由1和5与CO反应得到。化合物2和6在加热时消除苯,得到含有桥接SnPh 2