The reaction of square-planar, high-spin CrR[N(SiMe2CH2PPh2)2] (R = Me, CH2SiMe3) with alkyl halides (MeI, CF3CH2I, MeBr, PhCH2Cl) generates one-electron oxidation products Cr(R)X[N(SiMe2CH2PPh2)2], unusual examples of five-coordinate chromium(III) complexes. Cr(Me)Br[N(SiMe2CH2PPh2)2] and Cr(CH2SiMe3)Cl[N(SiMe2CH2PPh2)2] have been structurally characterized. Alkylation of the latter complex with LiCH2SiMe3
方平面,高自旋CrR [N(SiMe 2 CH 2 PPh 2)2 ](R = Me,CH 2 SiMe 3)与烷基卤化物(MeI,CF 3 CH 2 I,MeBr,PhCH 2 Cl )生成单电子氧化产物Cr(R)X [N(SiMe 2 CH 2 PPh 2)2 ],这是五配位
铬(III)配合物的不寻常例子。Cr(Me)Br [N(SiMe 2 CH 2 PPh 2)2 ]和Cr(CH 2 SiMe 3)Cl [N(SiMe 2CH 2 PPh 2)2 ]在结构上已得到表征。后者的络合物与LiCH 2 SiMe 3的烷基化得到五配位的Cr(III)二烷基络合物Cr(CH 2 SiMe 3)2 [N(SiMe 2 CH 2 PPh 2)2 ],其在结构上也被表征。试图分离空间上不受阻碍的Cr(III)二烷基(例如二甲基)配合物导致分解。过量的PhCH的加成2 CI至[(PH 2 PCH