Complexes with Platinum−Iridium Bonds: Stepwise Formation of a PtIr2 Cluster Complex
摘要:
The reaction of [Pt(dppm)(2)]Cl-2 (dppm = Ph2PCH2PPh2) with [Ir(CO)(4)](-) and dppm in a 1:2:1 ratio leads in a multistep reaction to the new heteronuclear cluster complex [PtIr2(CO)(2)(mu-CO)(mu-dppm)(3)], which contains a triangle of metal atoms with each edge bridged by a dppm ligand and in which only the platinum atom is coordinatively unsaturated. The initial step in the reaction leads to formation of the neutral and cationic binuclear complexes [PtIrCl(CO)(2)(mu-dppm)(2)] and [PtIr(CO)(3)(mu-dppm)(2)](+), respectively. The binuclear complexes then react with additional [Ir(CO)(4)](-) to form the cluster [PtIr2(CO)(4)(mu-CO)(mu-dppm)(2)] by insertion into a Pt-P linkage; this cluster can exist in two isomeric forms, each containing a triangular PtIr2 group with the Ir-Ir and one Pt-Ir edge bridged by dppm ligands but differing in stereochemistry. These isomers equilibrate slowly at room temperature, and each reacts easily with dppm to form the final cluster complex [PtIr2(CO)(2)(mu-CO)(mu-dppm)(3)]. The structures of the complexes [PtIr2(CO)(2)(mu-CO)(mu-dppm)(3)], [PtIr(CO)(3)(mu-dppm)(2)][PF6], and one isomer of [PtIr2(CO)(4)(mu-CO)(mu-dppm)(2)] have been determined crystallographically, and the reaction sequence has been determined by monitoring reactions through NMR methods.