| 190264-58-5

• CAS: 190264-58-5
• 化学式: C₁₉H₃₆Cl₂RuSb
• 分子量: 558.221
• InChiKey: DVQCLRDCFVVXAK-UHFFFAOYSA-L

计算性质

• 辛醇/水分配系数(LogP)：
  None
• 重原子数：
  None
• 可旋转键数：
  None
• 环数：
  None
• sp3杂化的碳原子比例：
  None
• 拓扑面积：
  None
• 氢给体数：
  None
• 氢受体数：
  None

反应信息

• 作为反应物：
  描述：

  在 Mg-Hg 作用下， 以 四氢呋喃 为溶剂， 以29%的产率得到chlororuthenium(1+);1,2,3,4,5-pentamethylcyclopenta-1,3-diene;tri(propan-2-yl)stibane
  参考文献：
  名称：

  Halfsandwich‐Type Triisopropylstibane Ruthenium Complexes with 16‐, 17‐, and 18‐Electron Configurations and an Unsymmetrical Binuclear 18/16‐Electron Ru ₂ (Sb i Pr ₃ ) Species

  摘要：

  AbstractThe paramagnetic ruthenium complex [(η5‐C5Me5)RuCl2‐{SbiPr3}] (2), which is prepared from [(η5‐C5Me5)RuCl2]n (1) and SbiPr3, reacts with Mg/Hg in THF to give the coordinatively unsaturated 16‐electron species (η5‐C5Me5)RuCl)(SbiPr3)] (3). Compound 3 is obtained in much better yield from [(η5‐C5Me5)Ru(μ3‐Cl)]4 (4) and SbiPr3 (molar ration 1:4). While 3 reacts with CO to give the 18‐electron complex [(η5‐C5Me5)RuCl(CO)(SbiPr3)] (5), on treatment of 3 with HCˇO2Me the metallacycle [(η5‐C5Me5)RuCl{k2(C,C)‐C(CO2Me}=CHC(CO2Me)=CH}(SbiPr3)] (6) is obtained. The reaction of 4 with SbiPr3 in the molar ratio of 1:2 affords the binuclear compound [(η5‐C5Me5)(SbiPr3)Ru(μ‐Cl)2Ru(‐C5Me5)] (7). The molecular structures of 2 and 7 have been determined by X‐ray crystallography.

  DOI：

  10.1002/cber.19971300505
• 作为产物：
  描述：

  triisopropylantimony 、 二氯(五甲基环戊二烯基)合钌(III)聚合物 以 二氯甲烷 为溶剂， 以84%的产率得到
  参考文献：
  名称：

  Halfsandwich‐Type Triisopropylstibane Ruthenium Complexes with 16‐, 17‐, and 18‐Electron Configurations and an Unsymmetrical Binuclear 18/16‐Electron Ru ₂ (Sb i Pr ₃ ) Species

  摘要：

  AbstractThe paramagnetic ruthenium complex [(η5‐C5Me5)RuCl2‐{SbiPr3}] (2), which is prepared from [(η5‐C5Me5)RuCl2]n (1) and SbiPr3, reacts with Mg/Hg in THF to give the coordinatively unsaturated 16‐electron species (η5‐C5Me5)RuCl)(SbiPr3)] (3). Compound 3 is obtained in much better yield from [(η5‐C5Me5)Ru(μ3‐Cl)]4 (4) and SbiPr3 (molar ration 1:4). While 3 reacts with CO to give the 18‐electron complex [(η5‐C5Me5)RuCl(CO)(SbiPr3)] (5), on treatment of 3 with HCˇO2Me the metallacycle [(η5‐C5Me5)RuCl{k2(C,C)‐C(CO2Me}=CHC(CO2Me)=CH}(SbiPr3)] (6) is obtained. The reaction of 4 with SbiPr3 in the molar ratio of 1:2 affords the binuclear compound [(η5‐C5Me5)(SbiPr3)Ru(μ‐Cl)2Ru(‐C5Me5)] (7). The molecular structures of 2 and 7 have been determined by X‐ray crystallography.

  DOI：

  10.1002/cber.19971300505