Pd(dppf)(Ph)(I) (1, dppf = Ph2PC5H4FeC5H4PPh2) with 1.5 equiv of PPh2H leads to the formation of the Pd(II) dinuclear complex Pd2I2(μ-dppf)(μ-H)(μ-PPh2) (2) and the phosphines PPh3 and dppf. The reaction of 1 with 1 equiv of PCy2H (Cy = cyclo-C6H11) slowly gives Pd2I2(μ-dppf)(μ-H)(μ-PCy2) (3). Complex 2 reacts further with PPh2H to give the known [Pd(μ-PPh2)(I)(PPh2H)]2 (4). Reaction of Pd(dcpm)(Ph)(I) (dcpm
Pd(
DPPF)(Ph)(I)(1,
DPPF = Ph 2 PC 5 H 4 FeC 5 H 4 PPh 2)与1.5当量的PPh 2 H的反应导致形成Pd(II)双核络合物的Pd 2我2(μ-
DPPF)(μ-H)(μ-PPH 2)(2)和膦PPH 3和
DPPF。的反应1与1个当量的PCY 2 H(Y =环-C 6 H ^ 11)慢慢地给出的Pd 2我2(μ-
DPPF)(μ-H)(μ-PCY 2)(3)。复杂2个与PPH进一步反应2小时,得到公知的[将Pd(μ-PPH 2)(I)(PPH 2 H)] 2(4)。
钯的反应(DCPM)(PH)(I)(DCPM =赛扬2 PCH 2 PCY 2)与PPH 2 H,使得[
钯2(PPH 2 2H)2(μ-DCPM)(μ-PPH 2)] [I ](5)。加入Pd(
DMPE)(ME)(Cl)的处理(
DMPE =我2 PCH 2 CH 2 PME 2)用的AgOTf和PPH