The rhodium bis(boryl) complex
[RhCl(PPh
3
)
2
B(cat)}
2
] (cat =
1,2-O
2
C
6
H
4
) reacts with the diborane(4)
compounds B
2
(O
2
R)
2
O
2
R =
1,2-O
2
C
6
H
3
Me-4,
1,2-O
2
C
6
H
2
Bu
t
2
-3,5
and dimethyl-L-tartrate
[OCH(CO
2
Me)CH(CO
2
Me)O]} affording unsymmetrical
metal bis(boryls)
[RhCl(PPh
3
)
2
B(cat)}B(O
2
R)}] and diborane(4) compounds (cat)BâB(O
2
R),
one possible mechanism for which involves Ï-bond metathesis.
[RhCl(PPh3)2B(cat)}2](cat = 1,2-O2C6H4)与二
硼烷(4)化合物B2(O2R)2(O2R = 1,2-O2C6H3Me-4、1,2-O2C6H2But2-3,5以及二甲基-
L-酒石酸酯[OCH(CO2Me)CH(CO2Me)O])反应,生成非对称的
金属二
硼基[RhCl(PPh3)2B(cat)}B(O2R)}]和二
硼烷(4)化合物(cat)BâB(O2R),其中一种可能的机理涉及π键交换。