The reaction between (C6F5NHCH2CH2)2NH and methyl iodide in the presence of base leads to (C6F5NHCH2CH2)2NMe (H2[ArFNMe]) in good yield. Reactions between H2[ArFNMe] and MCl4 (M = Mo or W) in the presence of NEt3 yield pseudooctahedral paramagnetic compounds of the type [Et3NH][ArFNMe]MCl3}. The reaction between 3 equiv of MeMgCl and [Et3NH][ArFNMe]MoCl3} produced paramagnetic trigonal bipyramidal
在碱的存在下,(C 6 F 5 NHCH 2 CH 2)2 NH与甲基
碘之间的反应以良好的产率得到(C 6 F 5 NHCH 2 CH 2)2 NMe(H 2 [Ar F NMe])。在NEt 3存在下,H 2 [Ar F NMe]与MCl 4(M = Mo或W)之间的反应产生[Et 3 NH] [Ar F NMe] MCl 3 }型拟八面体顺磁性化合物。3当量的MeMgCl与[Et3 NH] [Ar F NMe] MoCl 3 }产生顺磁三角双锥体[Ar F NMe] MoMe 2。H 2 [Ar F NMe]和Mo(NMe 2)4之间的反应产生的是顺磁七坐标[(C 6 F 4(NMe 2)NCH 2 CH 2)2 NMe] MoF 2,而不是五坐标[[C 6 F 5 NCH 2 CH 2)2 NMe] Mo(NMe 2)2,而H 2 [Ar F NMe],[NEt 4 ] 2 [Re(O)Cl