| 246265-77-0

• CAS: 246265-77-0
• 化学式: C₃₆H₄₁ClOP₂Ru
• 分子量: 688.191
• InChiKey: NTPOFIHUHCOIDN-UHFFFAOYSA-M

计算性质

• 辛醇/水分配系数(LogP)：
  None
• 重原子数：
  None
• 可旋转键数：
  None
• 环数：
  None
• sp3杂化的碳原子比例：
  None
• 拓扑面积：
  None
• 氢给体数：
  None
• 氢受体数：
  None

反应信息

• 作为产物：
  描述：

  二氯(五甲基环戊二烯基)合钌(III)聚合物 、 二苯基膦 以 乙醇 为溶剂， 生成 、 、 chlororuthenium(1+);diphenylphosphane;1,2,3,4,5-pentamethylcyclopenta-1,3-diene
  参考文献：
  名称：

  Synthesis, properties and crystal structures of pentamethylcyclopentadienyl- and cyclopentadienyl-ruthenium(II) diphenylphosphine complexes

  摘要：

  The synthesis, characterization and single-crystal structure determination of chiral compounds (eta(5)-C5R5)Ru(pHph(2))(pph(3))Cl (R = H 3, R = Me 4) and prochiral Cp * Ru(PHPh2)(2)Cl (6) are described. Compound 6 has been available from reaction of PHPh2 and several starting materials. The X-ray structure comparison between 3, 4 and 6 allowed us to compare the influence of the phosphine, Cp and Cp * ligands in these half-sandwich compounds. In addition, a structural investigation was carried out on Cp*R(NBD)Cl(7).

  DOI：

  10.1016/s0022-328x(96)06769-1

文献信息

• Investigation of the reactivity of the phosphorushydrogen bond in Cp′RuL1L2Cl complexes with diphenylphosphine ligands
  作者：Román Torres-Lubián、M.Jesús Rosales-Hoz、Atta M Arif、Richard D Ernst、M.Angeles Paz-Sandoval

  DOI：10.1016/s0022-328x(99)00191-6

  日期：1999.8

  compound Cp*Ru(H)(Cl)[(OPPh2)(POHPh2)] (10) or an aromatic ring of its coordinated phosphine will bind to the electrophilic [Cp*Ru]+ fragment to give compound [Cp*Ru[μ-(η6-C6H5)POHPh]Cp*Ru(POHPh2)Cl]Cl (8). Based on 1H- and 31P-NMR spectroscopic data, compounds with two different P-donor ligands have also been prepared, including Cp*Ru(POHPh2)(PHPh2)Cl (9), [Cp*Ru(POHPh2)2(PHPh2)]OTf (17) and Cp*Ru(POHPh2)(POEtPh2)Cl

  描述了由Cp * Ru（PHPh 2）2 Cl（1）的氧化，氯化，水解和乙醇化所产生的产物。1中的PH键氯化可分离出Cp * Ru（PClPh 2）2 Cl（6），并且有光谱学证据表明存在Cp * Ru（PClPh 2）（PHPh 2）Cl（5）。化合物1和5的水解得到二氢化物络合物[Cp * Ru（H）2（OPPh 2）（POHPh 2）]（13）和阳离子物质[Cp * Ru（PHPh 2）3 ] Cl（14）和[Cp * RuPOHPh 2（PHPh 2）2 ] Cl（15）。通过经由添加[Cp * Ru（PHPh 2）3 ] OTf（16）的中间体[Cp * Ru（MeCN）（PHPh 2）2 ] OTf（16）合成[Cp * Ru（PHPh 2）3 ] OTf（14'）证实了14的形成。在MeCN解决方案中，AgOTf为1。（Cp * RuCl 2）2（12）在EtOH中与两当量的PHPh