环戊二烯基环易位发生在甲苯中的[Ca(C 5 Me 5)2 ]和[Ln(C 5 H 5)3 ]络合物之间,从而生成混合环化合物[Ln(C 5 Me 5)2(C 2 H 5) ](Ln 1 -La,1 -Nd)。1- Nd已经通过X射线衍射表征为空间上拥挤的单体。[Ca(C 5 Me 5)2(thf)x ]和[La(C 5 H 5)之间仅交换一个环在甲苯中的3(thf)x ]产生[La(C 5 Me 5)C 5 H 5)2(thf)](2)。与[M(C 5 H 5)2 ](MSn,Pb,Mn)反应,[Ca(C 5 M 5)2(thf)x ]产生相应的[M(C 5 Me 5)2 ]配合物。K [C 5 Me 5 ]与[La(C 5 H 5)3(thf)],[Sn(C 5 H 5)2 ]和[Pb [C 5 H 5)2 ]在甲苯中分别得到环交换产物2,[Sn(C 5 Me 5)2 ]和[Pb(C 5
Cyclopentadienyl ring metathesis with bis(pentamethylcyclopentadienyl)calcium as a route to mixed ring organolanthanide complexes; the crystal structure of (C5Me5)2Nd(C5H5)
作者:Pamela S. Tanner、David J. Burkey、Timothy P. Hanusa
DOI:10.1016/0277-5387(94)00316-7
日期:1995.1
Bis(pentamethylcyclopentadienyl)calcium, (C5Me5)2Ca, can be made by the reaction of Ca[N(SiMe3)2]2 with C5Me5H in toluene. It undergoes cyclopentadienyl ring metathesis with tris(cyclopentadienyl)lanthanide complexes, Cp3Ln (Ln = La, Nd, Sm) in toluene to generate the mixed ring complexes (C5Me5)2LnCp. The X-ray crystal structure of (C5Me5)2NdCp shows that the complex is a sterically crowded monomer
双(五甲基环戊二烯基)钙(C 5 Me 5)2 Ca可以通过Ca [N(SiMe 3)2 ] 2与C 5 Me 5 H在甲苯中的反应制得。它与三(环戊二烯基)镧系元素络合物CP 3 Ln(Ln = La,Nd,Sm)在甲苯中进行环戊二烯基环复分解反应,生成混合环络合物(C 5 Me 5)2 LnCP。的(C的X射线晶体结构5我5)2 NDCP表明该复合物是一个在空间上拥挤的单体η 5 -C5 Me 5和CP环。C 5 Me 5和CP环的平均NdC距离为2.76–2.79Å。