[(η5-C5H5)ErCl2] | 166660-83-9

• 英文名称: [(η5-C5H5)ErCl2]
• 英文别名: (η5-Cp)ErCl2
• CAS: 166660-83-9
• 化学式: C₅H₅Cl₂Er
• 分子量: 303.261
• InChiKey: SNEWFOJLKWVKFI-UHFFFAOYSA-L

计算性质

• 辛醇/水分配系数(LogP)：
  None
• 重原子数：
  None
• 可旋转键数：
  None
• 环数：
  None
• sp3杂化的碳原子比例：
  None
• 拓扑面积：
  None
• 氢给体数：
  None
• 氢受体数：
  None

反应信息

• 作为反应物：
  描述：

  四氢呋喃 、 [((Ph2P)2N)K(tetrahydrofuran)(n)] 、 [(η5-C5H5)ErCl2] 以 四氢呋喃 为溶剂， 生成 [(η5-C5H5)Er(NPh2)2(N(PPh2)2)2K2(tetrahydrofuran)4]2
  参考文献：
  名称：

  Lanthanide−Potassium Wheels

  摘要：

  Mixed potassium-lanthanide wheel-shaped-structured, hexanuclear coordination oligomers of composition [(eta(5)-C5H5)Ln(NPh2)2-{N(PPh2)(2)}(2)K-2(THF)(4)](2) (Ln = Er (1a), Yb (1b)) and an octanuclear coordination polymer of composition [(eta(5)-C5H5)Sm(NPh2)(2){N(PPh2)(2)}K](infinity) (2) were synthesized. All presented compounds can be obtained in moderate yields in a one-pot procedure, in which the potassium salts KNPh2 and [K(THF)(n)N(PPh2)2] as well as NaC5H5 are reacted with anhydrous samarium, erbium, and ytterbium trichloride in THF.

  DOI：

  10.1021/ic050557l

文献信息

• Chemistry of C-Trimethylsilyl-Substituted Heterocarboranes. 32. Synthetic and Structural Investigations on Half-Sandwich Lanthanacarboranes:  Important Synthons in Metallacarborane Chemistry
  作者：Jianhui Wang、Joanna Smith、Chong Zheng、John A. Maguire、Narayan S. Hosmane

  DOI：10.1021/om060268k

  日期：2006.8.1

  X = Br; m = 1, n = 0; 6, Ln = Pr, X = Br; m = 2, n = 1; 7, Ln = Nd; X = Cl, m = 2, n = 1; 8, Ln = Sm; X = Br, m = 2, n = 0; 9, Ln = Gd; X = Cl, m = 2, n = 1; 10, Ln = Tb, X = Cl, m = 2, n = 1; 11, Ln = Dy, X = Cl, m = 2, n = 1; 12, Ln = Ho, X = Cl, m = 2, n = 1; 13, Ln = Er, X = Cl, m = 2, n = 1; 14, Ln = Tm, X = Cl, m = 2, n = 1; 15, Ln = Yb, X = Cl, m = 2, n = 1; 16, Ln = Lu X = Cl, m = 2, n = 1)

  单钠复合碳硼烷前体nido -1-Na（C 4 H 8 O）-2-（R）-3-（SiMe 3）-2,3-C 2 B 4 H 5（R = SiMe 3（1）或Me（2））与大量的镧系元素卤化物进行了研究。LnCl 3（或LnBr 3）与1以1：2的摩尔比在60°C的干燥THF中反应生成二聚半三明治镧碳硼烷络合物[2,3-（SiMe 3）2 -1-X-1 - （THF）米-1-LN（η 5 -2,3--C 2乙4 H 4）] 2 · n（THF）（3，Ln = Y，X = Cl，m = 2，n = 1; 4，Ln = La，X = Br; m = 1，n = 0; 5， Ln = Ce，X = Br; m = 1，n = 0; 6，Ln = Pr，X = Br; m = 2，n = 1; 7，Ln = Nd; X = Cl，m = 2，n = 1; 8，Ln = Sm; X = Br，m = 2，n