The reaction of
[Ru(PCHBu
t
)Cl(CE)(PPh
3
)
2
] (E = O,
S) with [AuX(PPh
3
)] (X = Cl,
CCC
6
H
4
Me-4), HgCl
2
or
Hg
2
Cl
2
leads via addition of the Au–X
or Hg–Cl bonds across the Ru–P linkage to the heterodinuclear
phosphaal- kene complexes
[RuP(AuPPh
3
)CHBu
t
}ClX(CE)(PPh
3
)
2
] and
[RuP(HgCl)CHBu
t
}Cl
2
(CE)(PPh
3
)
2
].
Ru(P
CHBu t)Cl(CE)(PPh 3 ) 2 ](E = O,S)与 [AuX(PPh 3 ) ](X = Cl,CCC 6 H 4 Me-4)反应、HgCl 2 或 Hg 2 Cl 2 通过 Au-X 或 Hg-Cl 键与 Ru-P 连接,生成异核
磷醛烯配合物 [RuP(AuPPh 3 )
CHBu t }ClX(CE)(PPh 3 ) 2 ] 和 [RuP(HgCl)
CHBu t }Cl 2 (CE)(PPh 3 ) 2 ]。