Abstract The reaction of [(NdI)3N2] (I) with Cp3Er in the presence of sulfur in THF gave CpNdI2(THF), NdI(S2N2)(THF), and an unidentified erbium compound. A similar reaction of [(DyI)3N2] yielded CpDyI2(THF) and ErI(S2N2)(THF). When I reacted with ErCl3, the clusters [Nd2ErClI4-(S2)(S2N2)(THF)7] and [Nd2ErCl2I3(S2)(S2N2)(THF)7] were formed in 33–34% yield. From the mixture of reaction products of [(DyI)3N2]
摘要 [(NdI) 3 N 2 ] ( I ) 与 Cp 3 Er 在
硫的存在下在 THF 中的反应得到 CpNdI 2 (THF)、NdI(S 2 N 2 )(THF) 和一种未鉴定的
铒化合物。[(DyI) 3 N 2 ]的类似反应产生CpDyI 2 (THF)和ErI(S 2 N 2 )(THF)。当我与 ErCl 3反应时,簇 [Nd 2 ErClI 4 -(S 2 )(S 2 N 2 )(THF) 7 ] 和 [Nd 2 ErCl2 I 3 (S 2 )(S 2 N 2 )(THF) 7 ] 的生成率为 33 – 34%。从[(DyI) 3 N 2 ]与
硫和NdI 3的反应产物的混合物中,仅[Nd 2 DyI 5 (S 2 )(S 2 N 2 )(THF) 7 ]以较小的产率分离并鉴定. 在所选条件下,二
碘化
铕 EuI 2几乎不与络合物I和
硫发生反应。起始 EuI 2 (50%) 和先前表征的集群